(2)C3x(C 1x)2=x(x？ 1)(x？ 2)6x2= 16(x+2x？ 3).

∵x>0，x+2x≥22。

If and only if x=2, the equal sign holds.

When x=2, C3x(C 1x)2 gets the minimum value.

(3) Nature ① cannot be generalized. For example, when x=2, C 12 is defined, but C2? 12 is meaningless;

Property ② can be generalized in the form of Cxm+Cxm- 1=Cx+ 1m, where m is a positive integer.

Actually, when m= 1, there is CX1+cx0 = x+1= CX1.

When m≥2. . Cmx+Cm？ 1x=x(x？ 1)……(x？ m+ 1)m！ +x(x？ 1)……(x？ m？ 2)(m？ 1)!

=x(x？ 1)……(x？ m+2)(m？ 1)! 【x？ m+ 1m+ 1]=x(x？ 1)……(x？ m+2)(x+ 1)m！ =Cmx+ 1。

Variant: Solution: (1) A-153 = (-15) (-16) (-17) =-4080;

(Ⅱ) Both properties ① and ② can be generalized in the following forms:

①Axm=xAx- 1m- 1，②Axm+mAxm- 1 = Ax+ 1m(x∈R，m∈N+)

In fact, in ①, when m= 1, the left =Ax 1=x, and the right =xAx- 10=x, the equation holds;

When m≥2, the left side = x (x-1) (x-2) (x-m+1).

= x[(x- 1)(x-2)((x- 1)-(m- 1)+ 1)]= xAx- 1m- 1，

Therefore, ①Axm=xAx- 1m- 1 holds;

In ②, when m= 1, the left side = ax1+ax0 = x+1= ax+1= right side, and the equation holds;

When m≥2,

left = X(X- 1)(X-2)(X-M+ 1)+MX(X- 1)(X-2)(X-M+2)。

= x(x- 1)(x-2)(x-m+2)[(x-m+ 1)+m]=(x+ 1)x(x- 1)(x-2)。

Therefore, ② axm+maxm-1= ax+1m (x ∈ r, m∈N+) holds.

(iii) Derive first to get (ax3)' = 3x2-6x+2.

Let 3x2-6x+2 > 0, x < 3? 33 or x > 3+33.

Therefore, when x∈ (? ∞,3? 33), which is an incremental function,

When x∑(3+33, +∞), the function is also increasing function.

Let 3x2-6x+2 < 0, and you get 3? 33