The resistivity ρ of copper is: ρ=0.0175 (in Ω-mm?/m)

Assuming that the cross-sectional area of the copper wire is S (in mm?), and the length is L (in m),

The resistance R of this section of the wire is: R=ρL/S

Knowing that: S=1.5mm? and L=100m.

Substituting the above formula, we have:

R=0.0175(Ω-mm?/m)×100(m)/1.5(mm?)=7/6(Ω)≈1.1667Ω

However, the above calculations are for reference only.

The actual calculation also takes into account the temperature, the number of strands of copper wire, the purity of the material of the copper wire, the frequency of the current ...... and other parameters.