Intcount (int A [12], int B [12], int year, int month, int day)// define a counting function to calculate what day it is today, A [12], B [12].

{

The code is a little long, sorry, please add it if you have any questions, thank you.

int i，sum = 0；

If (year% 4 = = 0 & amp& amp year% 100! =0||year%400==0)// Judge whether it is a leap year. If so, make the following statement.

for(I = 0； I & ltmounthi++)

{

sum+= a[I]；

}

other

for(I = 0； I & ltmounthi++)

{

sum+= b[I]；

}

Total+= days;

Returns (the sum);

}

void main()

{

Int year, month, day, m;

int a[ 12]={3 1，29，3 1，30，3 1，30，3 1，30，3 1，30，3 1}，b[ 12]={3 1，28，3 1

//a array is the number of days per month in leap year, and B array is the number of days per month in non-leap year.

Printf ("Please enter year, month and day \ n");

Scanf("%d, %d, %d ",& year & month & Day);

M = Count (A, B, Year, Month, Day);

printf("%d\n "，m)；

}