Suppose the minimum circle radius is r,? The radius of the second largest circle is r, then? r+R=8

The half circumference of the smallest circle is: 3. 14Xr.

Similarly, the half circumference of the second largest circle is 3. 14XR.

Then the perimeters of these two small semicircles are: 3.14xr+3.14xr = 3.14x (r+r) = 3.14x8.

Plus 4X3. 14 half circumference of the outer circle.

The final result is 12X3. 14=?