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Chemical equation for incomplete combustion of methanol in oxygen
8CH3OH+nO2====mCO2+2CO+16H2O 3.6g of water is produced.

Solution:

(1) 8 moles of methanol contains 8 moles of carbon atoms, according to the conservation of C atoms, it is known that 2 moles of carbon monoxide, so 6 moles of carbon dioxide, i.e., m = 6

Substitution, we get n = 11

(2) Let the oxygen that participates in the reaction when generating 3.6 g of water is n'g, according to the equation of the reaction, we can have:

11O2 <. ----> 16H2O

352 < ------> 288

n' < --------> 3.6

Leaving the ratio to find n' = 4.4 (g)